Colin Mitchell
We
would now like to take a look at the function of the model, particularly, frequencies
with respect to our two parameters,
, the density of the string, and T, the tension of the string.
Earlier, we defined
. Let's look at the n-th mode of
vibration, namely,
.
If we notice the trigonometric identity
,
we see that we can use it to reduce the harmonic to
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Here,
and
are arbitrary
constants that could be defined, but it is not important to where we are
going. If we have the solution in this
form, we have one trigonometric function in x,
and one trigonometric function in t. Since the frequency we seek is the cycle of
transverse vibrations in the string over time, we will look at the time
function. Doing this, we notice that the
frequency of the n-th mode is
![]()
Using a known fundamental frequency (
), which is used to tune stringed musical instruments, we can
find the necessary tension necessary to tune a string with a given
density. Solving for T, we get
![]()
Now,
we should take care of the physical units in this equation. We will measure
in grams/meter, L as meters, and
as Hertz (
). Putting these into
the equation, we get

This translates into gram-meters/second2. One Newton of force is equal to
, so our force will be
measured in milliNewtons.
As an example, imagine we would like to tune a guitar string to concert A, which has a frequency of 440Hz. Also, we know that our guitar string has a density of 100gr/m, and that the string is 1m long. Then we have
